Finding formula for differential dy and linear approximations, please check my work.
It's a little dark, sorry!
There's one more part which I will upload in just a moment :)
Ah, now I see the boo boo.
f'(5)= woops, you dropped the 3 that was in the back
ah!
Besides that, looks good :) You can see that this `red line` approximates your curve very well around x=5. https://www.desmos.com/calculator/ttlbwonl4o
so it would be 3/32
Ya, the f'(5) is the only thing that should change, instead of 1/32 you get 3/32 because of that 3 we lost earlier.
Part c.. hmm
em yeah so the formula changes and the answer to part c changes
Oh good call :)
to 1.999 lol
wait huh
that is the same answer o.o
oh some of the decimal numbers change.
well the ....ten thousands place will have changed :) instead of 1.9997 you should get 1.99906 or something like that, ya?
yyep yep so i guess I can write 1.9991
does it all look good now? :)
Oh wait, mine is giving me another 9... 1.99990625 lemme make sure I didn't mess something up..
2+(3/32)(4.99-5)
\[\large\rm f(4.99)\approx f(5)+f'(5)(4.99-5)\]\[\large\rm f(4.99)\approx 2+\frac{3}{32}(-0.001)\]
Ya looks good ^^
-0.01* hehe my bad :)
Excellent! thank you.
Join our real-time social learning platform and learn together with your friends!