Question

algebra 2 help please!

Answer 1

subtract 2 from both sides and then square and see what you get

Answer 2

note: \[\sqrt{x} = x^{1/2}\]

Answer 3

the correct answer is x=22 but I don't understand the steps on how they got that

Answer 4

Start off by subtracting 2 on both sides what do you get

Answer 5

\[\sqrt{x-6=4}\]

Answer 6

Good, \[\sqrt{x-6} = 4\]

Answer 7

Now square both sides, remember sqaure root just mean it's to the power of 1/2, so square both sides cancels out the square root, \[\left( \sqrt{x-6} \right)^2 = 4^2\] so what does the equation look like now?

Answer 8

\[^{2}\]\[x^{2}-36=16\]

Answer 9

Hmm, not quite \[\left( \sqrt{x-6} \right)^2 \implies \left( (x-6)^{1/2} \right)^2 = (x-6)^{2/2} = (x-6)\]

Answer 10

So we have \[x-6=16\]

Answer 11

finish it off

Answer 12

x=22 ?

Answer 13

Bingo, adding 6 on both sides we're left with x = 22