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Find abs extrema
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\[f(x)=\frac{ 4 }{ x^2+1 }\]
interval is [-1,3]
find the derivative
I would use quotient rule and then find the critical numbers right?
yes
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for my derivative I got x^2+1-8x over (x^2+1)^2
no
oh wait would it be -8x on top?
yes
so my critical number is zero?
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yes
then my abs max is (0,4) and my abs min is (3,2/5)?
yes
oh you are my man! thanks for stopping by! and btw why does it take a while for people to answer my questions now?
depends on who is online
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When I first used this site around 3 years ago, I got help in about 5-10 mins
quite a few people that help are also college students and this time of year is really busy for them too.
ahh that makes sense, well thanks for answering my questions!
no problem
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