Question

I am willing to work. I want to learn. I will post document as well as possible answers once the post becomes active.

Answer 1

Ok, so I know the standard algebra formula y = mx + b. This is of course is used when you are given the slope + two points on the graph/line. But, I have reason to believe that y = mx + b is the incorrect way to go about solving this problem. For instance, y = 7x + b --- 0 = 7 (4) + b --- 0 = 28 + b --- -28 – 0 = 28 -28 + b --- y = 7x – 28. This is obviously not an answer choice, but I would like to learn. I am willing to contribute to the problem.

Possible answers:

(4, 6)

(0, 2)

(6, 4)

(2, 0)

Answer 2

first write the equation of line

Answer 3

y = 7x - 28?

Answer 4

\[\large \bf eq.of~line \rightarrow y-y_1=m(x-x_1)\]
where, \[\large \bf (x_1,y_1)~are~co-ordinates~through~which~line~is~passing\]

Answer 5

y - 0 = m ( x - 4)?

Answer 6

correct !

Answer 7

substitute `m` also !

Answer 8

y - 0 = 2 ( x - 4)...

Answer 9

Good job !

Answer 10

now, all you have to do is satisfy points in the equation of line,if they satisfy the equation, then that point is your possible answer :)

Answer 11

So, we would technically 'plug' in the values, observing if they fulfilled the equation or not?

Answer 12

yup

Answer 13

Would it be ok, if I test one out using one of the answers?

Answer 14

why not

Answer 15

Quick question, would I distribute the 2 (distributive property) or work out the equation within the parentheses first and then multiple? Thank you.

Answer 16

its your choice

Answer 17

its better to work within the parentheses

Answer 18

Working with (4, 6) I get 6 = 2, which is not correct. Can I keep going done the line @mayankdevnani?

Answer 19

yupp

Answer 20

Correct answer: (6, 4).

Answer 21

Good job :)

Answer 22

Thank you for your help! Would it be ok if I asked you a fairly similar question @mayankdevnani? I understand if your not available.

Answer 23

you can post it(only few minutes i am available)

Not from earth... lol

Answer 24

Ok @mayankdevnani. If you get around to it I appreciate it.

Answer 25

Consider two points :-
\[\large \bf (x_1,y_1)~and~(x_2,y_2)\]
\[\large \bf Slope=\frac{y_2-y_1}{x_2-x_1}\]

Answer 26

-1 + 5 = m ( -1 - 2)
-1 + 5 / -1 + 2

Answer 27

The top one is the equation of the line and the bottom one is y2 -y1 / x2 - x1. Please let me know if I'm wrong, I would be more than happy to learn...

Answer 28

your equation of line is wrong dude

Answer 29

where is variable x and y ??

Answer 30

and for determining slope, you don't need to write the equation of line

Answer 31

Ok, your right an equation of a line is NOT needed. In that case if we followed the y2-y1 / x2-x1 formula, and 'pluged' in the points given to us from the problem wouldn't it be -1 + 5 / -1 - 2 (accounting for the double negative rule)?

Answer 32

correct !!

Answer 33

In that case our answer should be 4/-3 as the slope, right?

Answer 34

yupp

Answer 35

Thanks again! I have one more problem just like the one above. I would work it out myself, but would like you to check it. Before you said you only had a few minutes so I understand if you can't. Thanks again...

Answer 36

your welcome :)

Answer 37

i have to go now !!

Answer 38

Ok. Thanks!

Answer 39

Nice to see you again :)