Question

Help please and fast if possible.


The height of the Empire State Building is 318.00 meters. If a stone is dropped from the top of the building, what is the stone's velocity just before it strikes the ground?

–1.75 meters/second

–18 meters/second

–79 meters/second

–636 meters/second

Answer 1

do you need help still?

Answer 2

@J.Maule

Answer 3

..

Answer 4

this answer is by @textbooktactics
Assuming there is no wind resistance and the stone has no initial velocity, use the equation
V2f=V2i+2a(xf−xi)

Or you should have some other equation that looks like it.
Vf is the final velocity we are looking for.
Vi is the initial velocity, which is zero
a is the acceleration due to gravity (9.81)
xi is the starting spot for the stone (0)
xf is the final location for the stone (318)
plug it all in and solve for Vf
v2f=(0)2+2(9.81)(318−0)

V2f=6239.16

Vf=79m/s

Answer 5

Although this was a debated answer so you might want to check it using the formula yourself.

Answer 6

sorry @magicremix123 I wasn't at school when you messaged this. my apologize

Answer 7

its okay :)

Answer 8

but yes I do need help @magicremix123

Answer 9

I am going to my next class, i will be available at 11 if that alright??

Answer 10

Im not sure I may be at PT. its alight. I may be able to get it now