Question

Help in graphing! (MEDAL!!!)


f(x) = -(x - 1)^2 + 4

Answer 1

\[\large f(x) = -(x - 1)^2 + 4\]

Answer 2

@Nnesha

Answer 3

what's the vertex point ?

Answer 4

I couldn't figure that out.

Answer 5

alright \[\huge\rm y=a(x-h)+k\] vertex form of quadratic equation
where (h,k) is the vertex and a tells us whether the graph opens up or down
if a is negative then opens down (vertex = maximum point )
if a is positive then opens up (vertex=minimum point )

Answer 6

a=leading coefficient

Answer 7

And how do I figure out the vertex?

Answer 8

there is a typo wait

Answer 9

i meant to type this \[\huge\rm y=a(x-h)^{\color{Red}{2}}+k\]

Answer 10

How do i figure out the vertex?

Answer 11

what number is replaced by h and k in ur equation ?

Answer 12

1 and 4

Answer 13

so (1,4) is the vertex?

Answer 14

that's correct

Answer 15

for the other points, do i just plot those points in to \(\large -(x-1)^2 + 4\) ?

Answer 16

that's the maximum point now find x-intercept and y-intercept
make a table
now just y values when x = 0 ,1,2,3