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Mathematics 22 Online
OpenStudy (anonymous):

I don't understand the explanation I'm given. Can someone help me for a medal?

OpenStudy (anonymous):

I'll post it in just a second

OpenStudy (anonymous):

OpenStudy (anonymous):

How did they get from 1. to 2. ? I get a different derivative when I solve it out

OpenStudy (jahmiya):

@superman38 do you understand this

OpenStudy (anonymous):

uh naq just lookin at it

OpenStudy (anonymous):

I just need the first derivative. Everything else, I can probably do on my own.

OpenStudy (anonymous):

It obviously provides it, but I'm curious to know how that got that as their answer.

OpenStudy (campbell_st):

so do you know what the 2nd derivative test is...?

OpenStudy (campbell_st):

ok.. so if \[g(x) = 2x^2(1 - x^2)\] if you distribute it can be written as \[g(x) = 2x^2 - 2x^4\] now take the derivative \[g'(x) = 4x - 8x^3\] so in factoring this 4x has been taken out as the common factor \[g'(x) = -4x(-1 + 2x^2)~~~~~or~~~~~~g'(x) = -4x(2x^2 - 1)\]

OpenStudy (anonymous):

OH! Factoring! I kept getting 4x - 8x^3 and couldn't figure out what to do next. Thank you. It makes sense now.

OpenStudy (anonymous):

(by the way, I wasn't watching my computer, so that's why I didn't respond when you originally posted. sorry about that)

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