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Mathematics 15 Online
OpenStudy (cutiecomittee123):

To solve 5sin(2x)=3cosx you should rewrite it as?

OpenStudy (sweetburger):

I think you can substitute sin(2x) for 2sin(x)cos(x) then you have 10sin(x)cos(x) = 3 cos(x)

OpenStudy (sweetburger):

from there you can do this 10sin(x)cos(x) - 3cos(x) = 0 Now bring together like terms.

OpenStudy (cutiecomittee123):

I think that works

OpenStudy (sweetburger):

I wrote that wrong factor out like terms*

OpenStudy (smilie2015):

by using half angle formula it will be answer B

OpenStudy (cutiecomittee123):

5sinx+3cosx=0?

OpenStudy (cutiecomittee123):

@smilie2015

OpenStudy (sweetburger):

I ended up at cosx(10sinx - 3) = 0

OpenStudy (cutiecomittee123):

Yeah that is a valid answer because its on the choices

OpenStudy (mathmale):

Please go back to the original question posted by cutie. Note that there is a trig identity for the double angle sine formula: sin 2x = 2 sin x cos x. Use this identity in the given equation. Figure out how to solve this. Note that there will be more than one solution.

OpenStudy (mathmale):

Note: In the long run, you are trying to solve for x (which is an angle). But this question only asks you to re-write the given equation to make this solution easier.

OpenStudy (mathmale):

@sweetburger : You were right all along, from your very first response. :)

OpenStudy (cutiecomittee123):

okay I got it, thanks guys!

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