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OpenStudy (sweetburger):
I think you can substitute sin(2x) for 2sin(x)cos(x) then you have 10sin(x)cos(x) = 3 cos(x)
OpenStudy (sweetburger):
from there you can do this 10sin(x)cos(x) - 3cos(x) = 0 Now bring together like terms.
OpenStudy (cutiecomittee123):
I think that works
OpenStudy (sweetburger):
I wrote that wrong factor out like terms*
OpenStudy (smilie2015):
by using half angle formula it will be answer B
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OpenStudy (cutiecomittee123):
5sinx+3cosx=0?
OpenStudy (cutiecomittee123):
@smilie2015
OpenStudy (sweetburger):
I ended up at cosx(10sinx - 3) = 0
OpenStudy (cutiecomittee123):
Yeah that is a valid answer because its on the choices
OpenStudy (mathmale):
Please go back to the original question posted by cutie. Note that there is a trig identity for the double angle sine formula: sin 2x = 2 sin x cos x.
Use this identity in the given equation. Figure out how to solve this. Note that there will be more than one solution.
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OpenStudy (mathmale):
Note: In the long run, you are trying to solve for x (which is an angle). But this question only asks you to re-write the given equation to make this solution easier.
OpenStudy (mathmale):
@sweetburger : You were right all along, from your very first response. :)