Question

which point is a solution to the system of inequalities y2x-3

Answer 1

Which point is a solution to the system ?

(3, 3)

(2, -1)

(-1, -2)

(-4, 1)

Answer 2

these are answers

Answer 3

also need help anther question will give medal

Answer 4

question 2

Answer 5

Which of the following systems correctly describe the system of inequalities graphed below?
graph of a system of two linear inequalities, first line is a solid line that passes through points (6, 0), (9, 2), and beyond, second line is a dotted line passes through (5, 3), (6, 3), and beyond, graph is shaded in the region that includes point (2, 8)

Answer 6

https://static.k12.com/eli/bb/652/1_34206/2_36287_9_34219/1fb802d2abf55c24064b2998d641312f55d956ce/media/106aae8c59bfe4a126e7e0f57ffd67631647f1e9/mediaasset_1155512_1.jpg

Answer 7

this is the graph

Answer 8

these are multiple choice answers
A y>3
Y>=2/3x-4

Answer 9

b y<3
y>=2/3x-4

Answer 10

c y>3
y<=2/3-4

Answer 11

d y<3
y<=2/3-4

Answer 12

the shaded region, is given by the intersection of the subsequent regions:
1) a first region which is given by all points whose \(y-\) coordinate is greater than \(3\)
2) a second region which is given by all points have the \(y-\) coordinate which is greater than the corresponding \(y-\) coordinates of the slanted line, so, we have to write the equation of such slanted line first

Answer 13

oops.. by all points whose \(y-\) coordinate is greater than the corresponding \(y-\)coordinate of the slanted line...

Answer 14

now, the slanted line passes at points \((0,-4)\) and \((6,0)\), so its equation is:
\[\frac{{y - {y_1}}}{{{y_2} - {y_1}}} = \frac{{x - {x_1}}}{{{x_2} - {x_1}}}\]
where \((x_1,y_1)=(0,-4)\) and \((x_2,y_2)=(6,0)\)
Please substitute those coordinates into my equation, and write the equation of slanted line, so we can continue to write the solution of the exercise

Answer 15

so then 0,4
6,0

Answer 16

is this the first question or second one

Answer 17

no, please they are \((0,-4)\) and \((6,0)\)
it is the second one

Answer 18

oh ok sorry

Answer 19

hint:
here is next step:
\[\frac{{y - \left( { - 4} \right)}}{{0 - \left( { - 4} \right)}} = \frac{{x - 0}}{{6 - 0}}\]
please simplify

Answer 20

another step:
\[\frac{{y + 4}}{4} = \frac{x}{6}\]
please continue, now it is easy

Answer 21

1( y2 + x3 )2

Answer 22

If I multiply both sides by \(4\) I get:
\[y + 4 = \frac{{4x}}{6}\]
and then:
\[y + 4 = \frac{{2x}}{3}\]
so the equation of slanted line is:
\[y = \frac{{2x}}{3} - 4\]
am I right?

Answer 23

x6+y

Answer 24

oh yea i messed up o my multiplying

Answer 25

so the region of the exercise, is the region of all points whose \(y-\) coordinate is greater than \(3\) and it is greater than \(2x/3 - 4\)
So, what is the right option?

Answer 26

oops... I meant is greater or equal than \(2x/3 -4\)

Answer 27

hint:
if \(a\) is greater than \(b\) I write \(a >b\)

Answer 28

it would leave d or c

Answer 29

I'm sorry, they are both wrong options

Answer 30

those are the only ones with greater than or equal sign

Answer 31

likemyou wrote

Answer 32

you have to search for this symbols \(>\) and \( \geqslant \)

Answer 33

please try

Answer 34

yeah thats what this means <= or >=

Answer 35

it a or c

Answer 36

its c then @Michele_Laino

Answer 37

as I wrote before, C is a wrong option

Answer 38

i meant to say a

Answer 39

correct!

Answer 40

sorry i am dumb thank you for your patcience @Michele_Laino

Answer 41

hi and it was wrong it was b

Answer 42

thanks for helping though

Answer 43

thanks!! @Cruznatalie150
option B, is a wrong option @daisyduck04

Answer 44

no i am actually talking about the question she helped me with

Answer 45

ok! :) @daisyduck04

Answer 46

before i go @Michele_Laino how
would i solve the first one

Answer 47

just tell me my steps u dnt have to help me you done enough already

Answer 48

@Michele_Laino

Answer 49

hi your in k12?

Answer 50

why did you block me

Answer 51

for example, point \((3,3)\) is not the right option, since its coordinates don't check the inequality \(x<y\)

Answer 52

did you just substitute them to check

Answer 53

in order to solve such exercise, you have to search for point, whose coordinates verify contemporarily both the inequalities

Answer 54

correct! @Cruznatalie150 we have to substitute into both inequalities

Answer 55

so then @Michele_Laino

Answer 56

let's consider the second point \((2,-1)\), such coordinates verify the first inequality \(y<x\)?

Answer 57

i tried it work because -1<2 right so then it would be that one because i tried others

Answer 58

@Michele_Laino

Answer 59

now we have to substitute into the second inequality, please try

Answer 60

oh wait thats right and i did and it didnt work

Answer 61

-1>1 thats nt true

Answer 62

correct! Then let's consider the third point and please repeat the same procedure

Answer 63

it works @Michele_Laino for the first one because-2<-1 but i got stuck in the 2 equation

Answer 64

-2>2(-1)-3

Answer 65

aand got -2.-1

Answer 66

for second inequality, we have:
left side y= -2
right side = \(2 \cdot (-1)-3=-2-3=-5\)
so what can you conlcude?

Answer 67

then i tried the 4 one it didnt work eaither

Answer 68

so, what is the right option?

Answer 69

its c because a negative times negative is a positive right

Answer 70

@Michele_Laino

Answer 71

correct! It is option C