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The thin uniform rod in the figure below has length 9.0 m and can pivot about a horizontal, frictionless pin through one end. It is released from rest at angle θ = 39° above the horizontal. Use the principle of conservation of energy to determine the angular speed of the rod as it passes through the horizontal position.
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Someone tell me why i'm wrong. Here is my work.
I see that rod spin almost like a disk so I=(mr^2)/2
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