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Physics 12 Online
OpenStudy (ac3):

The thin uniform rod in the figure below has length 9.0 m and can pivot about a horizontal, frictionless pin through one end. It is released from rest at angle θ = 39° above the horizontal. Use the principle of conservation of energy to determine the angular speed of the rod as it passes through the horizontal position.

OpenStudy (ac3):

OpenStudy (ac3):

Someone tell me why i'm wrong. Here is my work.

OpenStudy (ac3):

I see that rod spin almost like a disk so I=(mr^2)/2

OpenStudy (ac3):

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