Question

These 2 questions go hand in hand with each other


3x2 + 52 = 4
Step 2 to solve the equation would be:
Select one:
a. Multiply each side by 3 ((Incorrect))
b. Divide each side by 3
c. Take the multiplicative inverse of 4
d. Add 52 to each side

The final answer using imaginary and complex numbers would be:
Select one:
a. x = 16i Incorrect
b. x = 4i
c. x = ±4i
d. No solution

Answer 1

Is that 3 x 2 or 3x2?

Answer 2

3 multiplied by 2?

Answer 3

Wait a minute, is the 2 by any chance an exponent?

Answer 4

Oh yes! sorry the 2 is an exponent sorry

Answer 5

Yeah, I was confused there.

Answer 6

Okay, I think you're supposed to get the variable (x) isolated. So theoretically, you have to take 52, remove that and throw it on the other side to make a -52.

Answer 7

i know you subtract 52 on both sides but whats the next step i thought it was multiply 3 on each side

Answer 8

I'm pretty sure it's divide, since I remember something along the lines of "make exponent as small as possible."

Answer 9

oh okay and if you divide what do you get?

Answer 10

Divide -48 by 3.

Answer 11

its -16 i put +16 but thats wrong so itd be D no solution

Answer 12

And I think we've just solved your problem.

Answer 13

can you help me with this question..
An imaginary number:
Select one:
a. Is a real number Incorrect
b. Is a real solution
c. Is undefined
d. None of the above

Answer 14

Sure.

Answer 15

thanks !

Answer 16

https://en.wikipedia.org/wiki/Imaginary_number Imaginary numbers are like, these guys.

Answer 17

so D?

Answer 18

Possibly.

Answer 19

`its -16 i put +16 but thats wrong so itd be D no solution `

be careful @LegendaryNikki
just because there are no real solutions does not mean there are no solutions. An imaginary/complex solution is a solution

Answer 20

possibly?

Answer 21

I'm not entirely too sure.

Answer 22

yeah i used that defintion to answer it i got it wrong but can you help me with this one realll quick?
10x^2 = –90
i got -9 and it was wrong..

Answer 23

you forgot to take the square root of both sides

Answer 24

Are there other answers available?

Answer 25

a. ±3i
b. 3
c. –3i

Answer 26

Isn't the square root of ten like 3 point something?

Answer 27

3.16

Answer 28

And now I am genuinely confused.

Answer 29

@Nnesha , would it be possible for you to help?

Answer 30

me too

Answer 31

jim_thompson5910 -->> `you forgot to take the square root of both sides`
so ye...... take square root both sides to cancel out the square
suppose if it was x^3 then we have to take cube root both sides to cancel out the 3

Answer 32

im still lost so its 3?

Answer 33

do you know about imaginary number ?? i = what ?

Answer 34

So 3i means 3-what?

Answer 35

ohh well i was expecting an answer from here
but ye use the fact \[\rm i=\sqrt{-1}\]

Answer 36

her*

Answer 37

-3i

Answer 38

That's the answer?

Answer 39

here is an example \[\large\rm y^2 \rightarrow \sqrt{y^2} \rightarrow y^{2*\frac{ 1 }{ 2 }}\] we can convert radical to an exponent
that's how when we take square root it cancels out the square
\[\large\rm y^{\cancel{2}*\frac{ 1 }{ \cancel{2} }}= y\]
another example \[\sqrt{y^2}= 4 \rightarrow y= \pm2\]

Answer 40

how did you get -3i ?

Answer 41

Thank you guys !!

Answer 42

im sorry i gotta do something else but thanks so much ill figure it out in a little !!

Answer 43

Wait, -3i is the answer?

Answer 44

\[\rm \sqrt{-9} ~can~be~written~as~\sqrt{-1}*\sqrt{9}\]
use the fact i =sqrt{-1}
i guess u can take it from hre

Answer 45

I have absolutely no idea what I"m doing with this particular problem, actually.

Answer 46

\[10x^2 = –90 \Rightarrow x^2=-9\Rightarrow x=\pm\sqrt{-9}\Rightarrow x=\pm3i\]

Answer 47

there we go.

Answer 48

And problem solved.

Answer 49

what about that other one were we got -16? i still dont understand that one

Answer 50

it\s done the same way i did the one above