Question

WILL MEDAL AND FAN!!!!!
@pooja195 @magepker728 @myacute15 @magicremix123
In dogs, the color black is dominant to white and follows the rules of simple Mendelian inheritance. What would be the genotype ratio if a heterozygous black dog was crossed with a white dog?

A. 1 Black: 1 White

B. 2 Black: 2 Gray: 1 White

C. 1 Bb: 1 bb

D.1 BB: 2 Bb: 1 bb

Answer 1

@pooja195 @magepker728 @myacute15 @magicremix123

Answer 2

@Kainui @confluxepic help please

Answer 3

@TheSmartOne ?

Answer 4

@Rushwr FINALLY THANK GOD can you help please?

Answer 5

lol okai !!!!!!!!! Yeah what do u think the answer is ?

Answer 6

A or B?

Answer 7

Nop

Answer 8

Maybe d

Answer 9

Thanks pal!

Answer 10

we can get rid of B one shot
Here's the reason why!
The question clearly says the cross is according to simple Mendelian rules.
But in answer B you have an intermediate colour which is grey, that is incomplete dominance. Incomplete dominance is a variation from the Mendelian law. So B is wrong

Answer 11

If the dominant gene black is B and the recessive gene white b
Then the genotype of the heterzygous black colour individual is Bb
And the genotype of the white dog is bb ( that is because to show a recessive trait u need to have both in one parent)
Now will continue with the cross

Answer 12

SO the answer is C