There is no war in Ba Sing Se.
\[x^0 = 1 \] \[0^0 = 1? \]
Because, well, 0 . . .
0^0 = 1
No, 0^0 is undefined
0^0=0^1/0^1=0/0=infinity
thesmartone you are not smart xD
you cannot divide by 0
You can't deal with intermediate forms algebraically
\[0^0=\frac{ 0^1 }{ 0^1 }=\frac{ 0 }{ 0 }=\infty \]
err as in pre calculus uh what
0 is the exception for this rule
So 7^7 is the same as 7/7? I didn't know that.
no
7^7=7*7*7*7*7*7*7*7 not 7/7
They always just say if the exponent is 0, it equals 1 but they never really gave an explanation with it so I couldn't tell what 0^0 was
because x cannot be 0
7^7=7^14/7^7
I meant 7^0 not 7^7 woops
yes
WOOpS
because 7^0=7^1/7^1-7/7=1
woops i meant =
not -
First of all, great question. \[0^0\] This is what's called an indeterminate form. We can't say anything about what this means unless it shows up in a specific context! There are times when \(0^0=1\) and there are other times where \(0^0=0\) and it can be other things as well! How do we determine what its true value is then? That's what calculus allows us to answer.
It is uncertain , and mathematics is about certainities , so it is mathematically undefined
Like the same way you cannot divide by 0 :)
One way to side step the problem is to define exponents to tell you how many times you multiply the number by 1. For instance: \[a^b\] This means multiply \(a\) by \(1\) for \(b\) times. An example of this is: \[2^3 = 1*2*2*2\]\[2^1 = 1*2\]\[2^0=1\] \[0^3 = 1*0*0*0\]\[0^1 = 1*0\]\[0^0 = 1\]
this is a mystery
using what kainui said 0^0=1 using the main method 0^0=infinity
0^0 is same as 0/0
That's a pretty clear way to explain it, makes a lot of sense now. Ofc this will always be a weird question and probably has a lot of answers, but that's one clear way. But yeah, I guess it does depend on context.
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