Question

How to simplify B) and K) ?
Please help, will medal & fan.
http://s18.postimg.org/etaous861/image.jpg

Answer 1

Been a while sinece I've done this.. :P

Answer 2

Don't we need to find x?

Answer 3

Lol try again next tiem get shrekd skrub 360 noscope 420 blazin it oh baby a triple

Answer 4

Hm..?

Answer 5

Hm it says to simplify

Answer 6

Um, @CheesecakeKitten I'm going to have to ask you not to be rude.

Answer 7

Ah, simplify.

Answer 8

I tried to do, but i dont get the right answer:/

Answer 9

Sorry, I was a little busy.

Answer 10

@Michele_Laino Can you help this nice person here? Its been atleast a couple years since I've done this. Thanks.

Answer 11

Im back. AQualified Helper is coming, after they finish another question.

Answer 12

\[\frac{ x ^{\frac{ 1 }{ 2 }}-4 }{ x-16 }\times \frac{ x ^{\frac{ 1 }{ 2 }}+4 }{ x ^{\frac{ 1 }{ 2 }}+4 } =\frac{ \left( x ^{\frac{ 1 }{ 2 }} \right)^2-4^2 }{ \left( x-16 \right)\left( x ^{\frac{ 1 }{ 2 }} +4\right) }\]\[=\frac{ x-16 }{ \left( x-16 \right)\left( x ^{\frac{ 1 }{ 2 }}+4 \right) }=\frac{ 1 }{ x ^{\frac{ 1 }{ 2 }}+4 }\]

Answer 13

Sur, thanks for helping Cherry, whereas I couldn't.

Answer 14

for question k), we can use this identity:
\[\Large {a^{4/3}} - {a^{1/3}} = {a^{1/3}}\left( {{a^{\frac{4}{3} - \frac{1}{3}}} - {a^{\frac{1}{3} - \frac{1}{3}}}} \right) = {a^{1/3}}\left( {a - 1} \right)\]

Answer 15

namely, I have factored out

\[\huge {a^{\frac{1}{3}}}\]

Answer 16

\[\frac{ a ^{\frac{ 4 }{ 3 }}-a ^{\frac{ 1 }{ 3 }} }{ a-1 }=\frac{ a ^{\frac{ 1 }{ 3 }+1}-a ^{\frac{ 1 }{ 3 }} }{ a-1 }\]
\[=\frac{ a ^{\frac{ 1 }{ 3 }}a-a ^{\frac{ 1 }{ 3 }} }{ a-1 }=\frac{ a ^{\frac{ 1 }{ 3 }}\left( a-1 \right) }{ a-1 }\]
?

Answer 17

so, after a substitution, we get:
\[\huge \frac{{{a^{4/3}} - {a^{1/3}}}}{{a - 1}} = \frac{{{a^{\frac{1}{3}}}\left( {a - 1} \right)}}{{a - 1}} = ...?\]