question belowwwwww .-.
last one
so we see \(\sf\Large\frac{1}{8}\) on the right hand side that means we need to have a negative exponents for it to become a fraction, right?
.. idk tbh .-.
remember this rule? \(\bf \Huge a^{-b} = \frac{1}{a^b}\)
yes even tho i dont really get it
ok, first let's understand the rule better :)
xD ok
That's a rule to be learned and remembered. Understanding will come later.
i have to understand it to truly learn it tho @mathmale
For example, \(\bf\Huge 5^{2} = 5 \times 5\) But, that's positive exponents. When we have negative exponents, we merely flip it. So \(\bf\Huge 5^{-2} = \frac{1}{5^2} = \frac{1}{5\times 5}\)
okayy ... so what do i need to do xD
So, now for your question. :) Let's first find out how many times we need to multiply 2 to get 8 So \(\sf \Large 2^x = 8\) What is x = ?
4
no x is not 4
2^4=2*2*2*2=16 actually
im so confused now ;-;
Melody, keep in mind that we're discussing EXPONENTIATION.
im not good at this ;-;
If 2^x = 8, our job is to find the unknown exponent, x.
idk how
One way of solving for the exponent x would be to re-write 8 as 2^3. This states that the cube of 2 results in 8. Note that 2*2*2 = 8. OK with that?
..... hang on
if \(\bf\Large 2^3 = 8\) What do you think \(\bf\Large 2^{-3} =?\) @melody1590
that's a good question, @TheSmartOne , but please let me finish my discussion with Melody. We are given 2^x = 8 and are asked to find the exponent x.
But note that 8 can be re-written as 2^3, or as 2*2*2. thus 2^x = 2^3 Since the bases are the same, we can omit them, which leaves x=3. That's it.
I need to log off for the time being. good luck to you.
Its b
Join our real-time social learning platform and learn together with your friends!