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Is this correct? LCD of rational expressions
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I think so.
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No thanks. I can wait. :)
OKay, good luck!
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@TheSmartOne
It's wrong :P
\(\large\color{#000000 }{ \displaystyle 5x^2=5\cdot x\cdot x }\) \(\large\color{#000000 }{ \displaystyle 15x=5\cdot 3\cdot x }\) yes, your answer is wrong
I thought so:(
The least common denominator, has to be divisible by both 5x^2 and 15x.
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^
So, first we look at what is the least common multiple of 5 and 15 and the lcm of x and x^2
LCM of 5 and 15 is 15, and LCM of x and x^2 is x^2
so the lcm of 5x^2 and 15x will be 15x^2 :D
:D Thanks!
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Anytime! :D
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