Question

Find the derivative of y
y=sin^-1 (3/t^2)

Answer 1

i suggest finding the derivative implicitly if you don't remember derivative for inverse sine function

Answer 2

What I got up to so far:
y'= -6t^-3/ cos y

I dont know where to proceed from there. :/

Answer 3

\[\sin(y)=\frac{3}{t^2} \\ \text{ or } \sin(y)=3t^{-2}\]

Answer 4

you are done unless you want to write y' in terms of t

Answer 5

only

Answer 6

you can do this by making a reference right triangle for the equation sin(y)=3/t^2

Answer 7

find adj
and then find cos(y)

Answer 8

okay, I got cos y= sqr (t^4-9) / t^2, so do i plug that into y' equals thingy?

Answer 9

you replace cos(y) with that yes

Answer 10

I got the same answer as the one in my textbook after doing that. Thanks! Now I know how to do this lol

Answer 11

cool stuff