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(1+sinΘ)(1-sinΘ)=cos^2Θ
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Help pls how do i make left side of the equation to equal to the right side
hello
Just expand the left hand side and you'll see it in fact is true \[\large (1 + sin\theta)(1 - sin\theta)\] \[\large 1 - sin\theta + sin\theta - sin^2\theta\] \[\large 1 - sin^2\theta\] So we have \[\large 1 - sin^2\theta = cos^2\theta\] Is this true? What do we know from the trig identity \(\large sin^2\theta + cos^2\theta = 1\)
ohh I see now!\
so it is expandable!
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thanks
No problem!
i thought i had to use identities lol
for these trig proofs you can use identities or expand... there are a lot of methods to try and make the left hand side = right hand side. It's just that some trig proofs are easier than others.
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