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Physics 16 Online
OpenStudy (korosh23):

Graphs of motion

OpenStudy (korosh23):

OpenStudy (korosh23):

@matt101 that area I pointed with arrows is confusing for me. In d-t it is increasing velocity, but in a negative direction, so v-t is a straight line below the o line. However, why the a-t graph is below the graph and not above the graph?

OpenStudy (matt101):

Look at the slope of the v-t graph during the time you indicated! It's a negative slope, meaning a negative acceleration! This makes sense, because according to the d-t graph, the displacement is DECREASING faster and faster over time, meaning the velocity is decreasing (or increasing in the negative direction, as you've said) over time as shown in the v-t graph, meaning there is a net negative acceleration as indicated in the a-t graph!

OpenStudy (korosh23):

I understand makes sense, so can we say that decreasing velocity in the positive direction and increasing velocity in the negative direction, have negative acceleration?

OpenStudy (korosh23):

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OpenStudy (matt101):

Correct! In both cases, the CHANGE in velocity over time is negative! And the graph you just posted shows a constant negative acceleration! If you apply a constant negative acceleration to an initially positive speed, that speed will get smaller and smaller (more negative) until it reaches 0 (stopped), but if you continue to apply that negative acceleration, the object will begin SPEEDING UP but in the NEGATIVE direction!

OpenStudy (korosh23):

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