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Mathematics 20 Online
OpenStudy (zenmo):

How do you simplify this?

OpenStudy (zenmo):

\[x(14-\frac{ x }{2 }-\frac{ \pi }{ 4 }x)+\frac{ \pi }{ 8 }x^2\] to get \[14x-\frac{ 1 }{2}x^2-\frac{ \pi }{ 8}x^2\]?

OpenStudy (zenmo):

I closed the question, and opened a new one in-case I made the question confusing.

Directrix (directrix):

I went back and verified part A. The question is now direct. My question to you is what happen to the pi term when you distributed the x? If you would write out the complete distribution of x over the 3 terms in the parentheses, I think you will see the error.

OpenStudy (zenmo):

\[x(14-\frac{ x }{ 2 }-\frac{ \pi }{ 4 }x)+\frac{ \pi }{ 8 }x^2\] = \[14x-\frac{ 1 }{ 2 }x^2-\frac{ \pi }{ 4 }x^2+\frac{ \pi }{ 8}x^2\]. I don't know how that would get the simplified version that I'm looking for.

ganeshie8 (ganeshie8):

Hint : \[\dfrac{\pi}{4} = \dfrac{2\pi}{8}\]

ganeshie8 (ganeshie8):

\(x(14-\frac{ x }{ 2 }-\frac{ \pi }{ 4 }x)+\frac{ \pi }{ 8 }x^2\) \(=14x-\frac{ 1 }{ 2 }x^2-\frac{ \pi }{ 4 }x^2+\frac{ \pi }{ 8}x^2\) \(=14x-\frac{ 1 }{ 2 }x^2-\frac{ 2\pi }{ 8 }x^2+\frac{ \pi }{ 8}x^2\)

ganeshie8 (ganeshie8):

now combine the last two terms

OpenStudy (zenmo):

Ah, I see it now. \[-\frac{ 2\pi }{ 8 }x^2+\frac{ \pi }{ 8 }x^2= -\frac{ 2\pi }{ 8 }+\frac{ 1\pi }{ 8}=-\frac{ \pi }{ }\]

OpenStudy (zenmo):

-pi/8

ganeshie8 (ganeshie8):

who ate x^2

OpenStudy (zenmo):

yea -(pi/8)x^2 **

OpenStudy (zenmo):

I was looking at a practice-version solution example, and I didn't know how they simplified this part. Thanks! :) Other then that, I understand on how to do the rest of the problem. Just needed a little refresh on simplication.

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