How many grams of chlorine gas (Cl2) are in a 17.8 liter sample at 1.1 atmospheres and 29 degrees C? can someone help me understand this...im not sure how to do it, i think it might be the percent catching me off guard...can someone explain to me how to get the answer?
@Rushwr can you help me with this?
use PV=nRT
let me tell u the easy way to solve these first write down the data u are given with We know the volume (V), Pressure (P) and temperature (T) R is the universal gas constant now u can see we know all the data needed except no. of moles (n) in PV=nRT equation right? We know moles = mass divided by molar mass Molar mass of Cl2 is approximately 71gmol^-1
first find the moles or else u can directly substitute m/M instead of n in the equation m= mass M= molar mass
Can u try and get the answer here !
ok give me a sec and ill try :)
how do i get the mass?
moles = mass divded by molar mass moles is the n in the equation instead of PV=nRT we can write the equation like PV=(m/M)RT right?
P = pressure = 1.1 atm V = volume = 17.8 L n = number of moles Cl2 (unknown) R = gas constant = 0.08206 L*atm/mol*K T = temperature = 29C + 273.15 = 302.15 K
ok that kinda makes sense...
these are the data. Make sure that u convert ur temperature to kelvin
where did the 273.15 come from?
\[PV= nRT\] \[n= \frac{ m }{ M }\] \[PV= \frac{ m }{ M }RT\]
When u convert a temperature from Celsius to kelvin u need to add 273.15 to the Celsius value to convert t to kelvin
I hope that makes sense. oh u can also add 273 approximately
so i would use that number every time i converted celcius to kelvin or just for this?
yes exactly
@AlexisIB Make sure that u are thorough with the conversions
ok what do i do with everything now? do i multiply?
do i keep it like it is?
now substitute the values
ok...not to sound stupid but how do i do that? :(
PV= nRT right? First we are gonna find moles (n) We know pressure (P) = 1.1 atm Volume (V) = 17.8L Universal gas constant (R) = 0.08206 L*atm/mol*K Temperature (T) = 29+273 = 302K
now get the value for n !
ok but i still dont know how...but ill call my teacher, thanks for helping me though
no problem . And sorry for late replies my OS is lagging
@Rushwr i think i figured it out without calling my teacher...can you check to see if im right so far?
@mayankdevnani can you check?
P=1.1 V=17.8 R=.0821 T=29' C + 273.15 = 302.15 K (always use 273.15 when converting from degrees to kelvin) 1.1 x 17.8 / 0.0821 x 302 =0.7895 Mass= .7895 mol x 70.906 g/mol
yup ! good job :) @AlexisIB
I'm sorry I was a little late for this. Anyways yeah great job @AlexisIB
thank you!!! im so happy that i actually did it!!
:)
both of you are awesome :)
lol thanks
you are awesome @AlexisIB
YOUR HARDWORK PAYS OFF !
Thanks!!
your welcome :)
Join our real-time social learning platform and learn together with your friends!