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Can someone please explain to me how to do this!? What is the volume, in liters, occupied by 0.485 moles of Oxygen gas at 23.0 oC and 0.980 atm?
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so for this one your going to use the equation PV=nRT 0.980(V)=0.485(0.0820574)(296.15) V=12.0267
Thank you sooooo much!!!
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