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Chemistry 22 Online
OpenStudy (marinebaby):

Can someone please explain to me how to do this!? What is the volume, in liters, occupied by 0.485 moles of Oxygen gas at 23.0 oC and 0.980 atm?

OpenStudy (anonymous):

so for this one your going to use the equation PV=nRT 0.980(V)=0.485(0.0820574)(296.15) V=12.0267

OpenStudy (marinebaby):

Thank you sooooo much!!!

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