what would the equation look like for the points (-.6, -3) and (-.6, 4)?
First find the slope. \(\sf\Large Slope = \frac{y_2-y_1}{x_2-x_1}\)
-6-4 -6-(-3)?
@TheSmartOne
is it 6 or 0.6?
umm what do you mean?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @abbycross167 what would the equation look like for the points (-.6, -3) and (-.6, 4)? \(\color{#0cbb34}{\text{End of Quote}}\) \(\color{#0cbb34}{\text{Originally Posted by}}\) @abbycross167 -6-4 -6-(-3)? \(\color{#0cbb34}{\text{End of Quote}}\) You are interchangely using .6 and 6... so which one is it?
6
ok, so what is y_1 and y_2?
-6 -3?
the points are in the form \(\sf\Large (x_1,y_1)~and~(x_2,y_2)\)
ok umm. so y2-y1/x2-x1 = -.6- (-3)/-.6-4
why do keep putting that dot before 6???
because that's how it was in my question. I looked back and figured it out
so is it 0.6 or is it 6.0 ??
because that dot makes a HUGE difference
-0.6
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