what would the equation look like for the points (-.6, -3) and (-.6, 4)?
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TheSmartOne (thesmartone):
First find the slope.
\(\sf\Large Slope = \frac{y_2-y_1}{x_2-x_1}\)
OpenStudy (abbycross167):
-6-4
-6-(-3)?
OpenStudy (abbycross167):
@TheSmartOne
TheSmartOne (thesmartone):
is it 6 or 0.6?
OpenStudy (abbycross167):
umm what do you mean?
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TheSmartOne (thesmartone):
\(\color{#0cbb34}{\text{Originally Posted by}}\) @abbycross167
what would the equation look like for the points (-.6, -3) and (-.6, 4)?
\(\color{#0cbb34}{\text{End of Quote}}\)
\(\color{#0cbb34}{\text{Originally Posted by}}\) @abbycross167
-6-4
-6-(-3)?
\(\color{#0cbb34}{\text{End of Quote}}\)
You are interchangely using .6 and 6... so which one is it?
OpenStudy (abbycross167):
6
TheSmartOne (thesmartone):
ok, so what is y_1 and y_2?
OpenStudy (abbycross167):
-6 -3?
TheSmartOne (thesmartone):
the points are in the form
\(\sf\Large (x_1,y_1)~and~(x_2,y_2)\)
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OpenStudy (abbycross167):
ok umm. so y2-y1/x2-x1 = -.6- (-3)/-.6-4
TheSmartOne (thesmartone):
why do keep putting that dot before 6???
OpenStudy (abbycross167):
because that's how it was in my question. I looked back and figured it out
TheSmartOne (thesmartone):
so is it 0.6 or is it 6.0
??
TheSmartOne (thesmartone):
because that dot makes a HUGE difference
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