Question

I need some help with an integral.

Answer 1

btw i know that the first one is -7

Answer 2

\[\int\limits_{-3}^{3}f(x)dx=\int\limits_{-3}^{-1}f(x)dx+\int\limits_{-1}^{1}f(x)dx+\int\limits_{1}^{3}f(x)dx\]

Answer 3

i only need help one the second half

Answer 4

\[\int\limits_{1}^{-1}f(x)dx=-\int\limits_{-1}^{1}f(x)dx\]

Answer 5

can you solve now?

Answer 6

uh no

Answer 7

do I do the same as I did in the first part?

Answer 8

\[\int_1^{-1}[2f(x)-6]dx =2\int_1^{-1}f(x)\,dx -6\int_1^{-1}dx \]

Answer 9

\[\int\limits_{1}^{-1}2f(x)dx-\int\limits_{1}^{-1}6dx\]
\[=-2\int\limits_{-1}^{1}f(x)dx+6\int\limits_{-1}^{1}dx\]

Answer 10

okay so I got -4....

Answer 11

\[=-2*-7+6[1-(-1)]=14+12=26\]

Answer 12

you got it.