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Mathematics 16 Online
OpenStudy (anonymous):

I need some help with an integral.

OpenStudy (anonymous):

OpenStudy (anonymous):

btw i know that the first one is -7

OpenStudy (anonymous):

\[\int\limits_{-3}^{3}f(x)dx=\int\limits_{-3}^{-1}f(x)dx+\int\limits_{-1}^{1}f(x)dx+\int\limits_{1}^{3}f(x)dx\]

OpenStudy (anonymous):

i only need help one the second half

OpenStudy (anonymous):

\[\int\limits_{1}^{-1}f(x)dx=-\int\limits_{-1}^{1}f(x)dx\]

OpenStudy (anonymous):

can you solve now?

OpenStudy (anonymous):

uh no

OpenStudy (anonymous):

do I do the same as I did in the first part?

OpenStudy (unklerhaukus):

\[\int_1^{-1}[2f(x)-6]dx =2\int_1^{-1}f(x)\,dx -6\int_1^{-1}dx \]

OpenStudy (anonymous):

\[\int\limits_{1}^{-1}2f(x)dx-\int\limits_{1}^{-1}6dx\] \[=-2\int\limits_{-1}^{1}f(x)dx+6\int\limits_{-1}^{1}dx\]

OpenStudy (anonymous):

okay so I got -4....

OpenStudy (anonymous):

\[=-2*-7+6[1-(-1)]=14+12=26\]

OpenStudy (anonymous):

you got it.

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