Help correct three Algebra questions. @TheSmartOne
@TheSmartOne
correctcorrect
and ur work ?? why do you think its A ?
os is so slow ;-; correct*
this one is wrong it says greater than, not greater than and equal to. same with less than. Not less than and equal to. :P
So A..?
\(\le\) less than or equal to \(\ge\) greater than or equal to \(\lt\) less than \(\gt\) greater than
again, it says less than. NOT less than and equal to :P so A is also wrong :P
D..?
boof them have to be be \(\sf < \) and \(\sf >\) so nope again :P
B.-5 < x <3 is the correct one..? How though? I for sure thought it would be D.
|dw:1448399345882:dw|
:)
x is greater than -5 Both mean the same: x > -5 -5 < x x is less than 3 Both mean the same: x < 3 3 > x You need to show that x is both greater than -5 and less than 3. If you use all signs as <, you can combine the statements into one single compound inequality. For x is greater than -5, we will use -5 < x For x is less than 3, we will use x < 3 We choose those specific inequalities because they both have the same inequality sign, <. -5 < x and x < 3 can be combined into a single compound inequality: -5 < x < 3
A is the correct one..?
Problem 3. We are told: "x is no more than 6." Is x greater than 6 or less than six? Also, can x be exactly 6?
Correct. If x is no more than 6, that means x can be 6 or less. For example: Jane is no more than 6 years old. That means that Jane can be 6 years old or less than 6 years old. If Jane's age is x, then \(x \le 6\).
A is correct for problem 3.
Awesome. cx thanks dude!
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