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How much force is required to move a sled 5 meters if a person uses 60 J of work? a. 300 N b.12 N c. 65 N d. 30 N
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We know that \[W=F \times d \times cos(\theta)\] assuming theta=0 we then solve and have \[F=\frac{W}{d}\] substitute known values to get: \[F=\frac{60J}{5m} = 12N\]
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