Question

One question about i..........................

Answer 1

ok so
i^2=sqrt{-1}^2=-1
BUT! i^2=sqrt{-1}*sqrt{-1}=sqrt{(-1)*(-1)}=sqrt{1}=1

Answer 2

so does it keep changing from 1 to -1?

Answer 3

\[i^2=\sqrt{-1}^2=-1\]
\[i^2=\sqrt{-1}*\sqrt{-1}=\sqrt{(-1)*(-1)}=\sqrt1=1\]

Answer 4

@jim_thompson5910 @Hero @amistre64 @ganeshie8

Answer 5

i = (-1)^(1/2)

i^2 =[(-1)^(1/2)]^2 = (-1)^1 = -1

i^3 = (-1)^(3/2) = (-1)^(2/2) (-1)^(1/2) = -i

i^4 = i^2 i^2 = (-1)(-1) = 1

Answer 6

hmm

Answer 7

you do not treat i as tho it is composed of parts .... i = sqrt(-1)

Answer 8

ok

Answer 9

\[i^2 =[\sqrt{-1}]^2\]
\[i^2\ne\sqrt{(-1)^2} \]

Answer 10

got it