Write a proof to show that a rectangle has congruent diagonals. Be sure to create and name the appropriate geometric figures. This figure does not need to be submitted.
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OpenStudy (leahhhmorgannn):
@AlexandervonHumboldt2
OpenStudy (alexandervonhumboldt2):
easy:
|dw:1448410177663:dw|
OpenStudy (alexandervonhumboldt2):
now we have that AD=BC, DC=AB, <D=<A=<B=<C.
OpenStudy (alexandervonhumboldt2):
thus triangle ADC=triangle BDC. Thus DB=AC
OpenStudy (alexandervonhumboldt2):
triangle ADC=BDC by 2 sides and an angle
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OpenStudy (leahhhmorgannn):
What are the reasons for all of that? I can't just state facts with a proof, can I?
OpenStudy (alexandervonhumboldt2):
AD=BC, DB=AC by because it is a rectangular.
OpenStudy (alexandervonhumboldt2):
DC=DC by reflexive property
OpenStudy (leahhhmorgannn):
so the definition of a rectangle
OpenStudy (alexandervonhumboldt2):
yes
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OpenStudy (alexandervonhumboldt2):
all angles of rectangular are 90
OpenStudy (alexandervonhumboldt2):
thus they are all congruent between themselves.
OpenStudy (alexandervonhumboldt2):
now we have enough info to say that the triangles are congruent by 2 pair sides and 1 pair angles.
OpenStudy (leahhhmorgannn):
so SAS for the triangles?
OpenStudy (alexandervonhumboldt2):
yes
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OpenStudy (alexandervonhumboldt2):
we use SAS to say that they are congruent.
OpenStudy (leahhhmorgannn):
okay. is that all there is, what you already listed?
OpenStudy (alexandervonhumboldt2):
well ok let me combine it all:
AD=BC, DB=AC by because it is a rectangular.
DC=DC by reflexive property
all angles of rectangular are 90°. <D=<A=<B=<C.
Thus the triangles are congruent by SAS. Thus AC=BD.