Question

Using a table of thermodynamics data, calculate delta heat rxn for
2SO + (2/3)O3 -->2SO2

Answer 1

So delta heat is products-reactions. Use the table and fill the values into this equation:2(value of SO2)-(2xvalue of SO+2/3xvalue of O3). Does this make sense?

Answer 2

What table though?

Answer 3

it is delta H so look up a delta H table for these values

Answer 4

I agree with @langenstroer you need to check a table of values for this.

Answer 5

Does it matter which one you use?

Answer 6

It should just be the standard enthalpy (delta H) table.

Answer 7

standard enthalpy of formation

Answer 8

http://www.webassign.net/chang10/6-table-04.gif

Answer 9

So this one would work?

Answer 10

yep it should work as long as it has the substances you need

Answer 11

Saw SO

Answer 12

SO2

Answer 13

SO2 = -296.1
O3 =142.2

Answer 14

2(value of SO2)-(2xvalue of SO+2/3xvalue of O3).
2(-296.1)-(2*.296.1 +2/3 * 142.2)

Answer 15

Does that look right?

Answer 16

yes that is right!

Answer 17

-84897.84

Answer 18

-592.2-84305.64

Answer 19

I got -1279.2 the 2nd time.

Answer 20

@Photon336

Answer 21

@langenstroer

Answer 22

\[2SO + \frac{ 2 }{ 3 } O3 -->2SO_{2}\]

Answer 23

@staldk3

\[\Delta H = \Delta H_{products}-\Delta H_{reactants}\]

Answer 24

@Photon336 Could you check my answer? It said -1279 was wrong.

Answer 25

@Data_LG2

Answer 26

I think the enthalpy of formation for SO is not there, so I'm not sure..
Take note that \(\sf SO\) is different from \(\sf SO_2\), so they will have different a \(\sf \Delta H°_f\)

Answer 27

\(\sf 2(-296.1) - 2/3(142.2)-2(\Delta H°_f\ {SO})\)

Answer 28

http://www.webassign.net/chang10/6-table-04.gif

Answer 29

So with a thermo chart would the SO be the S(monoclinic) one or is SO not on that chart?

Answer 30

I'm still viewing the question. For some reason it says I'm not.

Answer 31

@whpalmer4

Answer 32

I just search the std enthalpy of formation of sulfur monoxide and most of the sources says it is 5.01 kJ/mol, so probably you can use that value for your problem :)

\(\sf \Delta H_{rxn}=2(-296.1) - 2/3(142.2)-2(5.01)\)

Answer 33

the table should be provided to you by your school or in the textbook you're using

Answer 34

I think before we need to do the calculation, we need to establish concepts

Answer 35

@Data_LG2 I got -697.02

Answer 36

@Photon336

Answer 37

Yeah @hwyl is right.