Question

**Will Fan & Medal**
The mean of a population being sampled is 64, and and the standard deviation is 6.
If the sample size is 50, the standard error of the mean is?
. (Round off your answer to the nearest hundredth.)

Answer 1

Would it be something like this?

\(\Large \sigma _M = \frac{\sigma}{\sqrt{N}} \)?

Answer 2

Yeah but what should I plug in?

Answer 3

\(\Large \sigma = Standard~ Deviation \)

\(\Large N = Sample ~Size \)

Answer 4

Maleficent~Beastie

Answer 5

what is M?

Answer 6

\(\LARGE \sigma_M \) is just representing what you're looking for, it's the Standard Error of the Mean.

Answer 7

so i dont plug in anything? I'm confused now

Answer 8

Nope, it's just as if you y= (something something)

You don't do anything to it, it's just symbolizing what you're looking for

Answer 9

Ok I see, but how do I do this problem now?

Answer 10

Just plug in vales:

\(\Large \sigma = 6\)

\(\Large N = 50 \)


\(\Large \sigma_M = \frac{6}{\sqrt{50}}\)

Answer 11

*values

Answer 12

\[M=\frac{ 3\sqrt{2} }{ 5s } ?\]

Answer 13

then do i solve for s or simplify it?

Answer 14

o.O

What are you doing?

You just need to put \(\Large \frac{6}{\sqrt{50}} \) into a calculator.

Answer 15

is it going to be in decimal form?

Answer 16

for fraction i got : \[\frac{ 3\sqrt{2} }{ 5 }\]

Answer 17

decimal is 0.85

Answer 18

Yup, that's all you had to do (:

Answer 19

ok thanks!

Answer 20

No prob \(\Large \color{green}{\star} \)