Question

In this picture AB=?

Answer 1

i have no clue what distance is 70cm
and what distance is 50cm
and what distance is 175 cm

Answer 2

the top of that one cactus to the bottom of that other cactus 70cm?

Answer 3

The illustration is unclear. @amoodarya

Answer 4

and the top of the other cactus to the bottom of the other is 175cm?

Answer 5

maybe the burgundy line segment is 50cm ?

Answer 6

The given distances are probably heights

Answer 7

I'm guessing that A to the top of B is 175 cm and B to the top of A is 70 cm.
And 50 cm is probably the length of the purple.

Answer 8

Pawanyadav
can you show you work ?
there was multiple choice:
AB=200
AB=150
AB=100
AB=50

Answer 9

Wait a minute

Answer 10

I assume the point between A and B be M
Let AM=x BM=y
Then 50/70=y/(x+y). eq.(1)
And 50/175=x/(x+y). eq.(2)
Divided eq.2 by eq.1
70/175=x/y
2/5=x/y
y/5=x/2=k (let)
y=5k
x=2k
x+y=7k.
Stuck after this one equation is more required.

Answer 11

this was also my problem . it seems to be easy ,but ...
equations are not independent (I think )

Answer 12

is this trig or geometry?

Answer 13

Both can be used

Answer 14

i have a feeling that this is indeterminant

Answer 15

I don't know its origin (trig or geometry) but I want to solve it by every thing possible !

Answer 16

spose we take 2 line ...

L1: y = -mx+70, x intercept is at 70/m
L2: y = 175(m)/70 x

solving the system ...

175m/70 x = -mx+70

175m x = -70mx+70^2

x (245m) = 70^2

x = 70^2/(245m)

50 = 175(m)/70 * 70^2/(245m)

50 = 175 * 70/245 is true for all nonzero slopes