Question

area under curve again!

Answer 1

For the first one, is it: 1(f1)+2(F2)+3(f3)+4(f4) ?

Answer 2

@zepdrix :}

Answer 3

I just integrated it from 0 to 4, because I'm lazy

Answer 4

oooh I it's 1(f1)+1(f2) etc hahaaa blonde.

Answer 5

But you have the right idea, what did you get?

Answer 6

What do you need to know to finish solving this problem?
Note that the blue area of the left (first) curve is greater than the actual area under the graph. Likewise, the blue area of the right (second) curve is less than the act. area under the graph.

Answer 7

You are correct in identifying the width of each rectagular area as being 1.

Answer 8

Sorry, but I'll be off OpenStudy for a while.

Answer 9

Ok, so \[A \approx R_1+R_2+R_3+R_4\], \[\Delta x = \frac{ b-a }{ n }\] this is the width note n = 4 so we have \[A = \Delta x f(x_1)+\Delta x f(x_2)+...\]err yeah that looks about right

Answer 10

\[x_1, x_2,...=height\]

Answer 11

Indeed indeed

Answer 12

I got it :)

Answer 13

Ha great!