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Mathematics 15 Online
OpenStudy (anonymous):

Evaluate the integral

OpenStudy (anonymous):

\[\int\limits\limits_{-1}^{4}||x^2+x-6|-6| dx\]

OpenStudy (anonymous):

The double absolute values are tripping me up.

OpenStudy (tylerd):

you may be able to change the integration if theres symmetry. sec

OpenStudy (anonymous):

I can factor it but I don't see symmetry.

OpenStudy (anonymous):

I mean like how would I even do the cases?

OpenStudy (tylerd):

if you plug in -1 and 4, its always going to be negative, so we can simplify it to be -x^2+x+36

OpenStudy (anonymous):

Are you sure about that?

OpenStudy (anonymous):

CUz don't we have to break it into cases?

OpenStudy (tylerd):

you might be able to do that

OpenStudy (anonymous):

No. I get the wrong answer.

OpenStudy (tylerd):

what did you get

OpenStudy (anonymous):

Should be 71/6.

OpenStudy (anonymous):

got to split up the intervals and apply appropriate sign so that the function is positive

OpenStudy (anonymous):

Yes I got that. I factored the innermost quadratic but not sure how to deal with the outermost one.

OpenStudy (anonymous):

when is x^2 + x - 6 > 6 ?

ganeshie8 (ganeshie8):

you may solve below to get the numbers where the intgrand changes sign \[||x^2+x-6|-6| =0\]

OpenStudy (anonymous):

Did you mean greater than 0 pg? That's true for x<3 and x>2 .

OpenStudy (anonymous):

x<-3 sorry.

ganeshie8 (ganeshie8):

if you're allowed, you may simply graph it |dw:1448715042781:dw|

OpenStudy (anonymous):

No I cannot graph this haha.

OpenStudy (alekos):

I propose you go with ganeshie and integrate according to the graph

ganeshie8 (ganeshie8):

is it hard to solve : \[||x^2+x-6|-6| =0\] ? @Dido525

ganeshie8 (ganeshie8):

||x^2+x-6|-6| =0 |x^2+x-6|-6 =0 |x^2+x-6| =6

ganeshie8 (ganeshie8):

you can eyeball the solutions : x = -1, 3

OpenStudy (anonymous):

What about the negative case?

OpenStudy (anonymous):

Also don't we have to consider ++,+-, -+, +- ?

ganeshie8 (ganeshie8):

definitely, we need to consider all that and sketch the graph

ganeshie8 (ganeshie8):

||x^2+x-6|-6| =0 |x^2+x-6|-6 =0 |x^2+x-6| =6 x^2+x-6 = 6 or x^2+x-6 = -6 you can solve right ?

OpenStudy (anonymous):

Yes I can solve that. I think I have it. Hol don.

ganeshie8 (ganeshie8):

take ur time

OpenStudy (anonymous):

Okay I am pretty far. I got to: \[\int\limits_{-1}^4||x^2+x-6|-6|dx=\int\limits_{-1}^2|x^2+x|dx+\int\limits_{2}^4|(x+4)(x-3)|dx\]

OpenStudy (anonymous):

Aha! I got it :) .

OpenStudy (anonymous):

THanks everyone!

ganeshie8 (ganeshie8):

Awesome ! that integral looks perfect!

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