Using induction to prove that 2^x < x! for all x>=4
you know how to do a proof by induction?
if so, after the base case this takes one step if not, then it takes the rest of the night to explain it
why not for all x≥2?
cause \[2^2>2!\]
oh yes, I read the equation the other way around
factorial is greater!
well, you can tell that \(\large\color{#000000 }{ \displaystyle 2^4=16 }\) \(\large\color{#000000 }{ \displaystyle 4!=24 }\) multiply mutliply × 2 × larger and larger number every time every time
is totally obvious, but you have to understand the mechanics of a proof by induction if you know what they are, this one is solved in one step as @SolomonZelman wrote above if not, then it takes for ever
I recalled this logic from the very first proof of Harmonic Series Divergence - b/c that's the first time I've seen this.... I mean that: 1/5+1/6+1/7+1/8 is at least 1/8+1/8+1/8+1/8 and so on...
you are multiplying times number that is at least 2, for x!
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