Question

Please help? Will Fan + Medal!

Answer 1

The display uses five lines for each stem. Thus, "2t|" is the stem for palate widths of 22 and 23, "2f|" for 24 and 25, "2s|" for 26 and 27, and so on. (The "t" then stands for leaves that are twos and threes, the "f" for leaves of fours and fives, etc.) The mean palate width of this sample is 2.6 cm, and the standard deviation is 0.3 cm.

Answer 2

Assess the normality of the data as it pertains to the empirical rule.

Answer 3

your on your own with that question

Answer 4

@123AB456C If you aren't even going to try then kindly excuse yourself, please.

Answer 5

why

Answer 6

Anyone good with statistics? I'm almost understanding it, just needing a push in the right direction..

Answer 7

I forgot to mention that there are 124 palate widths. The goal is to see how well this data follows the 68-95-99 (Empirical) rule. The way I did it is this way: .68(124) =84.32 | .95(124) = 117.8 | .99(124) = 122.76. It feels as if I'm way off, however...

Answer 8

@123AB456C let's be nice! :) This is a friendly community let's make it a friendly environment too! Please don't be rude to users.If you don't know simply ignore
@Xaze im not sure about stats maybe @amistre64 knows :P

Answer 9

Thanks @pooja195 ^^

Answer 10

using the empirical rule, we would want to see if the stated percentage of the data is within the required number of deviations from the mean

Answer 11

it seems as tho we would need to determine the mean and standard deviation of the posted data in order to compare it tho

Answer 12

Well, it states that the mean = 2.6, Standard Deviation is 0.3 cm

Answer 13

well thats was nice of them :)

s, we would expect 68% of the data to be within 1 deviation of the mean:

mean +- 1sd would give us a range of data points to count out.

Answer 14

so, how much data is between 2.3 and 2.9 ?

Answer 15

Would it be the data between 2.3 and 2.9? As in, from 2.4 to 2.8?

Answer 16

i would make it inclusive; 2.3 to 2.9

Answer 17

Would it be 1.6? ((2.9-2.3)+1)=1.6

Answer 18

no. you actually have to count how many data points are from 2.3 to 2.9 [why?]

Answer 19

Oh... okay, I was trying to find the inclusive measure of range. So there would be 5 data points...?

Answer 20

i count 88 data points that have a value from 2.3 to 2.9

but these are old eyes and that is some tiny print.

Answer 21

Ah! I see. I'm way off then, haha. So, what's next?

Answer 22

i count 88 still ... so, is 88 out of 124 about 68%?

Answer 23

Yes, it's about 68%

Answer 24

then we can assume that about 68% of the data falls within1 standard deviation of the mean.

work the same process for 2 and 3 deviations from the mean

Answer 25

Just to make sure, would 2 deviations from the mean be 95% of the data? And 3 deviations would be 99%?

Answer 26

yep

Answer 27

What would points would I have to count between?

Answer 28

between 2 deviations of the mean

Answer 29

what is our mean? how much is 2 deviations?

Answer 30

Mean = 2.6. Two deviations would be... finding the data between 2.0 and 3.2, correct?

Answer 31

very good

Answer 32

we have 88 of them counted, so what is the number of extras?

Answer 33

21 extras?

Answer 34

31 extra, 88+31 = 119 data points about the mean. is that about 95% ?

Answer 35

Sorry *31. Typo. And... Yes, that is about 95%

Answer 36

very good. so what is our interval for 3 deviations about the mean?

Answer 37

And the next would be from 1.7 - 3.5. There would be 5 extras. 119+5=124

Answer 38

correct, and by observation all the data points fall in that interval

Answer 39

All right, thanks so much, you were a huge help! Here's the medal and fan, as promised. ^^

Answer 40

youre welcome :)