Question

anyone who is a master in solving WORK problems,please help me ^^

Answer 1

1. How many joules of work are done by a force in lifting a mass of 2kg. upward a distance of 3m.... Hmmm i think i need the FBD. and complete solution please help me, 14 problems to go...

Answer 2

@IrishBoy123

Answer 3

have you been given an equation for potential energy?

Answer 4

As @IrishBoy123 said, you need to use the equation for potential energy.

\[\huge \text{PE}=mgh\]m=mass
g=gravitational acceleration constant
h=height

However for work, that's not all. When you're measuring work, you're measuring how much energy it requires to get pushed from one potential energy to anotehr! Therefore,\[\huge \text{Work}=\Delta \text{PE}\]

Answer 5

Therefore its:
PE=2kg(9.8)(3m)
=58.8
And for work,
W=(58.8^2-0^2)
=3457.44

Answer 6

please check

Answer 7

The potential energy is correct, by why did you square it? \(\Delta\) is the symbol for simply "a change in." You were right to say that the final PE is 58.8 and the initial is 0

Answer 8

so how can i solve for Joules of work then?

Answer 9

You already did!

Answer 10

\[\huge \text{W}=\Delta \text{PE}=58.8-0\]

Answer 11

means we got 58.8 Joules as the answer?

Answer 12

Yes, but negative, I believe. I think the equation should be
\[\huge \text{W}=- \Delta \text{PE}\]
Try -58.8J

Answer 13

ok thanks ^^, can you help me for this 14 problems? :D

Answer 14

i will tag you fr the next problem, i will close this now ^^