Question

Given the equation Square root of 2x plus 1 = 3, solve for x and identify if it is an extraneous solution.

It would start with - 3 correct?

Answer 1

I'm after an explanation rather than answer here.

Answer 2

√2x+1=3, right?

Answer 3

Yes, @AlexDg3

Answer 4

does the square root apply to the 2x only or is it sqrt(2x + 1)?

Answer 5

\[\sqrt{2x+1} = 3\]

Answer 6

The first thing you have to do is square both sides of the equation to get 2x+1=9

Answer 7

How would 2x not be affected by the SQ?

Answer 8

because its under the square root

Answer 9

When you square it, it cancels the square root

Answer 10

Ah. So anything that isnt under a SQR is affected?

Answer 11

yes

Answer 12

Ah. So anything that isnt under a SQR is affected?

Answer 13

after you square it and get 2x+1=9, you solve for x

Answer 14

Ok, well this is looking for any extraneous answers, which in what I've understood in layman's terms is an answer that works on one half but not another.

Answer 15

x = 4, solution is extraneous
x = 4, solution is not extraneous
x = 5, solution is extraneous
x = 5, solution is not extraneous

thats what I was given.

Answer 16

And it would be x=5 not extraneous correct?

Answer 17

I don't think so. There is only one x, and it can only equal 4.

Answer 18

I think.

Answer 19

But isn't it square root then sum up what you have? (being after you square it and get 2x+1=9)

Answer 20

No, its four. you're right. I did it wrong.

Answer 21

4 not extraneous because x = 4 satisfies the equation

Answer 22

I had already figured it was non extraneous.