I'm not too sure how to approach this question.

Use Power series operations to find the Taylor series at x = 0 for the given function.

f(x) = x^2e^x

Question

I'm not too sure how to approach this question.

Use Power series operations to find the Taylor series at x = 0 for the given function.

f(x) = x^2e^x

anonymous · Answer

$$f(x) = x^2e^x$$

anonymous · Answer

f(x) = f(0) + f'(x)(x-0) + (f''(x)(x-0)^2)/2! +(f'''(x)(x-0)^3)/3! + ...

mathmale · Answer

Here you have a function which has the form of a product.  Please write out the power series for the exponential function, y=e^x.  Once you have a formula for that, you need only multiply it (or multiply each term) by x^2.   pgpilot is offering you another approach which is correct; it's the general form of a Taylor series with center at x=0.

anonymous · Answer

oh, e^x = 1+x + x^2/2! + ... just multiply out

anonymous · Answer

Great. thanks for the help