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Mathematics 15 Online
OpenStudy (anonymous):

HELP

OpenStudy (anonymous):

M is the midpoint of JK . The coordinates of J are (6, 3) and the coordinates of M are (-3, 4), find the coordinates of K.

pooja195 (pooja195):

Use the mid point formula :) \[\huge~\rm~\frac{ x_2+x_1 }{ 2},\frac{ y_2+y_1 }{ 2 } \]

OpenStudy (alexandervonhumboldt2):

substitute your values and solve

OpenStudy (alexandervonhumboldt2):

i gave you midpoint formula in previous question

OpenStudy (anonymous):

i don't get how to go backwards though

OpenStudy (alexandervonhumboldt2):

By law of openstudy, article Code of Coduct, paragraph 2 , i have a right to help the user even if someone is already helping him @TheSmartOne

OpenStudy (anonymous):

I understand who to find the midpoint but not find a point from the midpoint and end point

pooja195 (pooja195):

\[\bf\Large \frac{x-6}{2} = -3\]

OpenStudy (anonymous):

Would i use the distance formula then multiply the answer by 2? @AlexandervonHumboldt2

OpenStudy (sleepyhead314):

the distance formula is not necessary :) see the equation that pooja has given you? she has even plugged in (x1, y1) = (6, 3) and resulting (x , y) = (-3, 4) so we are trying to find the (x2, y2) can you take a look at the equation pooja just gave ans see if you can solve for x? :)

pooja195 (pooja195):

Here it is again \[\bf\Large \frac{x-6}{2} = -3\]

OpenStudy (anonymous):

That really doesn't help @sleepyhead314

OpenStudy (sleepyhead314):

what part are you still confused on then? :)

pooja195 (pooja195):

Here see if thinking about it like this helps. \[\huge~\rm~\frac{ 1 }{ 2 }x+\frac{ -6 }{ 2}=-3\]

pooja195 (pooja195):

What is -6/2?

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