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Integration The diagram shows the shaded region enclosed by the curve y=f(x) and a straight line y=2x.
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\[Given~\int\limits_{0}^{k}f(x)~dx=13\]and the area od the shaded region is 4unit^2,find the value of k.
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@ganeshie8
Represent the area, as the difference of the area determined by the parabola, minus the one determined by the line: \[\int\limits_{0}^{k}f(x)dx - \int\limits_{0}^{k}2xdx=4\] now, the area of the parabola is given, which is \(\int\limits_{0}^{k}f(x)dx=13\) so therefore: \[13-\int\limits_{0}^{k}2xdx=4\] \[\int\limits_{0}^{k}2xdx=9\] All you have to do know is calculate the integral on the left side and then solve the resulting expression for "k".
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\[k=3\]
Thank you @Owlcoffee :)
no problem.
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