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Mathematics 18 Online
OpenStudy (anonymous):

Integration The diagram shows the shaded region enclosed by the curve y=f(x) and a straight line y=2x.

OpenStudy (anonymous):

OpenStudy (anonymous):

\[Given~\int\limits_{0}^{k}f(x)~dx=13\]and the area od the shaded region is 4unit^2,find the value of k.

OpenStudy (anonymous):

of*

OpenStudy (anonymous):

@ganeshie8

OpenStudy (owlcoffee):

Represent the area, as the difference of the area determined by the parabola, minus the one determined by the line: \[\int\limits_{0}^{k}f(x)dx - \int\limits_{0}^{k}2xdx=4\] now, the area of the parabola is given, which is \(\int\limits_{0}^{k}f(x)dx=13\) so therefore: \[13-\int\limits_{0}^{k}2xdx=4\] \[\int\limits_{0}^{k}2xdx=9\] All you have to do know is calculate the integral on the left side and then solve the resulting expression for "k".

OpenStudy (anonymous):

\[k=3\]

OpenStudy (anonymous):

Thank you @Owlcoffee :)

OpenStudy (owlcoffee):

no problem.

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