Question

Please Help, I already know that the answer is not B. Will medal.

Answer 1

I have no idea how to separate h from the rest of the problem. I have already tried this, and answer is not B. hints the x over B. PLEASE HELP!

Answer 2

@AlexandervonHumboldt2 @Kainui Help? :(

Answer 3

@ShiBuringa

Answer 4

I do not know how to even begin to isolate h.

Answer 5

\[p = 0.7 (r h + b)\]you need to solve that for \(h\)

You can do just about anything as long as you do it equally to both sides of the equation.

But first, let's use the distributive property to get rid of the ( )

\[p = 0.7 r h + 0.7 b\]

Answer 6

Now, we can swap the stuff on the right and the left, as they are equal.

If \[a=b\]then \[b=a\]right?

\[p = 0.7rh + 0.7 b\]
\[0.7 rh + 0.7b = p\]
any question about that?

Answer 7

Okay, I didn't know if I should distribute or just try using the properties of equality.
so we have
p=0.7rh+0.7b

Answer 8

There are a number of routes we could take, but let's try this one, and maybe I'll do another one if this ends up being confusing.

\[0.7rh + 0.7b = p\]We want to get \(h\) alone on the left, so let's first move everything that does not contain \(h\) to the other side. We can do that by subtracting those terms from both sides:
\[0.7rh + 0.7b - 0.7b = p -0.7b\]\[0.7rh = p - 0.7b\]Good so far? Any ideas on what we do next?

Answer 9

Okay, makes sense. @whpalmer4
So now we have to divide r from 0.7rh
So would we divide it just as r or as 0.7r?

Answer 10

well, we need to get rid of both the 0.7 and the r, so we could divide by \(0.7r\) and do it all in one step:

\[\frac{0.7rh}{0.7r} = \frac{p-0.7b}{0.7r}\]what do you get when you simplify that?

Answer 11

\[h=\frac{ p-0.7b }{ 0.7r }\]

Correct?

Answer 12

yes

Answer 13

Wait I meant
\[h=\frac{ p-b }{ r }\]

because the 0.7 cancels out. Right?

Answer 14

No, that's not right. You can only cancel the 0.7 on the right hand side if it appears in all of the parts of the fraction:

for example:

\[\frac{0.7x + 0.7y}{0.7} = x+y\]
but \[\frac{0.7x + y}{0.7} \ne x+y\]
\[\frac{0.7x + y } {0.7} = \frac{0.7x}{0.7} + \frac{y}{0.7} = x + \frac{y}{0.7}\]

Answer 15

Okay, so what would be the correct answer, bc now I get it, I just don't know which answer is correct.

Answer 16

Yes, this is ugly, isn't it? :-)

Answer 17

B

Answer 18

@llama459 it is not B. because that is what I answered the first time I took this quiz and I was wrong.

Answer 19

we have \[h=\frac{ p-0.7b }{ 0.7r }\]

and our choices are
\[h = (\frac{p}{0.7}-b) \div r\]
\[h = \frac{p}{0.7}-b\div r\]
\[h = (\frac{p}{0.7})\div r - b\]\[h = \frac{p-b}{0.7}\div f\]

We know it is not B

Answer 20

C?

Answer 21

If we look at A, and multiply both sides by \(r\), we get

\[rh = \frac{p}{0.7} - b\]

If we multiply our solution by \(r\) on both sides we get

\[rh = \frac{p-0.7b}{0.7}\]

Answer 22

What happens if we split the fraction on the right as I did when I was showing you why your simplification was incorrect?

\[rh = \frac{p-0.7b}{0.7} = \frac{p}{0.7} - \frac{0.7b}{0.7} = \]

Answer 23

That simplifies to \[rh = \frac{p}{0.7}-b\]does it not? That appears to be one of your answer choices...

Answer 24

Uh, sorry, that itself does not appear to be one of your answer choices, but the equation we derived that from is the first answer choice.