Question

@misty1212
What is the discontinuity and zero of the function f(x) = the quantity of 2x squared plus 5x minus 12, all over x plus 4?

Answer 1

f(x) = (2x^2 + 5x - 12)/(x + 4)
as given, is not defined when the denominator is 0 ie when x + 4 = 0 or x = -4.

However, 2x^2 + 5x - 12 = (x + 4)*(2x - 3) so that the function can be simplified to (x + 4)*(2x - 3)/(x + 4) = 2x - 3

This has a zero when 2x - 3 = 0 ie 2x = 3 or x = 1.5

Answer 2

\[f(x)=\frac{2x^2+5x-12}{x+4}\]right?

Answer 3

\[f(x) = \frac{ 2x^2 + 5x - 12 }{ x + 4 }\]

Answer 4

yes :)

Answer 5

yeah that is what i thought

Answer 6

set the deniminator equal to zero \[x+4=0\] and solve for \(x\)
\[x=-4\]

Answer 7

it is not continuous at \(x=-4\)

Answer 8

same as what @muneeb180 said above

Answer 9

Discontinuity at (−4, −11), zero at (three halves , 0)
Discontinuity at (−4, −11), zero at (negative three halves , 0)
Discontinuity at (4, 5), zero at ( three halves , 0)
Discontinuity at (4, 5), zero at (negative three halves , 0)

Answer 10

these are my choices..

Answer 11

as for the zero, we have \[\frac{2x^2+5x-12}{x+4}=\frac{(x+4)(2x-3)}{x+4}=2x-3\]

Answer 12

discontinuity find by putting \(-4\) in to \(2x-3\) and get \[2(-4)-3=-8-3=-11\] so it is at \((-4,-11)\)

Answer 13

Ignore him

Answer 14

lol that child has never seen any in the flesh i am sure, only on porn sites

Answer 15

so we know its or A or B.

Answer 16

yeah and zeros are at \[2x-3=0\\
2x=3\\
x=\frac{3}{2}\]

Answer 17

lmfao so A,.. ok thanks ^-^

Answer 18

what @satellite73 said

Answer 19

go with A

Answer 20

:) thanks.

Answer 21

\[\color\magenta\heartsuit\]