The table below shows the distance d(t) in meters that an object travels in t seconds: (will include table below) What is the average rate of change of d(t) between 3 seconds and 5 seconds, and what does it represent? A. 59.5 m/s represents average speed of object between 3 secs and 5 secs B. 112 m/s represents average speed of object between 3 secs and 5 secs C. 112 m/s represents average distance object traveled between 3 secs and 5 secs D. 59.5 m/s represents average distance object traveled between 3 secs and 5 secs I don't really understand how to solve this.
Look up "average rate of change" and note how it is calculated. What is the distance traveled as time varies from 3 to 5 seconds? This info is easily calculated from info presented in the given table.
What is the time increment from 3 to 5 sec?
It would be 224, and then you divide it by 2 right (5-3 = 2)?
The ave. rate of change between 3 and 5 sec is the quantity (change in distance) / (change in time) with dimensions meters/seconds
So 112 and distance traveled?
Not quite. What is the difference in the distance traveled, from 3 to 5 seconds?
224?
Note: Do not use the distance associated with 4 sec. Y ou've done this twice. No. Rather, please subtract 126 from 350. 126 meters is the distance trav. after 3 sec, and 350 is the dist. trav. after 5 sec.
(350 m - 126 m) is the dist. traveled from time 3 sec to time 5 sec. Write the average rate of change as dist traveled during the period 3 to 5 sec ----------------------------------- Length of time interval
So you do 350 - 126?
Yes, as explained in my previous post.
Sincere apologies: your 224 m was correct; I was wrong.
Oh ok, I was confused for a second.
So, the change in distance divided by the change in time is what? This is your average rate of change over the period 3 to 5 seconds.
Please show your work. What is this average rate of change?
112 would be the average change. (350 - 126) 224 ---------- = ----- (5 - 3) 2
which would equal to 112
yes. be sure to include the units of measurement. I'd like to see (224 meters) / (2 seconds) = 112 m/s.
Thank you so much!
Happy to work with you. But I have to get off the Internet right now. You're welcome!
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