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Mathematics 24 Online
OpenStudy (anonymous):

What is the 6th term of the geometric sequence shown? 80, 40, 20, . . .

OpenStudy (sleepyjess):

Hello! Welcome to OpenStudy! Do you see a pattern happening here?

OpenStudy (anonymous):

no

OpenStudy (sleepyjess):

Well, what happens from 80 to 40?

OpenStudy (anonymous):

it goes down 20

OpenStudy (sleepyjess):

It is cut in half

OpenStudy (anonymous):

yah

OpenStudy (sleepyjess):

So what is half of 20? That will be the 4th number in the sequence

OpenStudy (anonymous):

10

OpenStudy (sleepyjess):

Good, now half of 10?

OpenStudy (anonymous):

then 5

OpenStudy (sleepyjess):

Yep, and lastly, half of 5 is?

OpenStudy (anonymous):

2.5 or 2 1/2

OpenStudy (sleepyjess):

Exactly!

OpenStudy (anonymous):

thank you so much

OpenStudy (sleepyjess):

No problem! :)

OpenStudy (sleepyjess):

Do you need any more help?

OpenStudy (alexandervonhumboldt2):

the formula for geometric sequence is \[A(n)=a*r^{n-1}\], where n is term number, A(n) is the nth term, ,a is first term, and r is common ratio

OpenStudy (anonymous):

no I should be good for know!

OpenStudy (sleepyjess):

Okay, you can give a medal to whoever you think gave the best explanation by clicking the blue "Best Response" button :)

OpenStudy (anonymous):

I did again thank you for the help :)

OpenStudy (alexandervonhumboldt2):

@Misam328 the method sleepyjess showed you is good. but if you have to find 50th term it will be hard to do this way. But you can use formula i gave for geometric sequence. For arithmetic it would look like \[a(n)=a_1+(n-1)*d\] where d is common difference, n is the number of term you want to find, and a_1 is first term

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