Find dy/dx, given x^2y^3 + 2 - 3y = x^2

would anyne know how to solve this equation step by step? im having trouble understanding how to find dy/dx

Question

Find dy/dx, given x^2y^3 + 2 - 3y = x^2

would anyne know how to solve this equation step by step? im having trouble understanding how to find dy/dx

anonymous · Answer

start with the product rule to get $$2xy^3+3x^2y^2y'-3y'=2x$$

anonymous · Answer

if that is not clear, let me know which step

anonymous · Answer

solve for $y'$ to finish it

anonymous · Answer

My answer came out to $$\frac{2x-2xy^3  }{ 3y^2x^2-3 }$$ yet the actual answer is $$\frac{ -2x-2xy^3 }{ 3y^2x^2-3 }$$ and im not sure where that negative came from? do you mind explaining how?