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Mathematics 21 Online
OpenStudy (diana.xl):

http://prntscr.com/99dfmp

OpenStudy (diana.xl):

@imqwerty

imqwerty (imqwerty):

Step 1-> plot the line \(\large y=-x+25\) Step 2->consider any point lying on either side of this line For example say (0,0) and enter these coordinates in the equation \(\large\ y < -x+25\) If it satisfies the equation then shade the area on the side which includes 0. Step 3->The boundary of the graph must be dotted and not solid. Remember that you get a graph with solid boundary only if there is an \(\color{red}{=}\) sign in the equation. But our equation \(\large y \color{red}{<} -x+25\) has '\(\color{red}{<}\)' so it will be dotted. Now try to plot it.

OpenStudy (diana.xl):

http://prntscr.com/99di79 like that?

imqwerty (imqwerty):

yes that is the 1st step an accurate pic for that step is -> http://prntscr.com/99djcv now try to do the \(Step~2\)

imqwerty (imqwerty):

we have to plot this inequality-> \(y <-x+25\) remember that whenever we plot inequality we get a shaded region We have already plotted the line \(y=-x+25\) http://prntscr.com/99djcv Now we need to find out which part to shade It can be either like this- http://prntscr.com/99dks2 or like this- http://prntscr.com/99dkwi So we have 2 ways We know that the points which lie in the correct graph must satisfy the inequality Now the point lying in the correct shaded region must satisfy the inequality So lets say that its shaded like this- http://prntscr.com/99dks2 its pretty clear that (0,0) lies in this graph in shaded region so (0,0) must satisfy the inequality \(\color{blue}{y<-x+25}\) so we put the coordinates of (0,0) in the inequality to check we get this- \(y<-x+25\) \(0<-(0)+25\) \(0<25 \) we see that the inequality holds true for (0,0) so it must lie in the graph and thus this is correct- http://prntscr.com/99dks2 ok till here?

OpenStudy (diana.xl):

http://prntscr.com/99dnez is this correct?

imqwerty (imqwerty):

yes correct so far Now the 3rd Step try to figure it out :)

OpenStudy (diana.xl):

http://prntscr.com/99drn9

OpenStudy (diana.xl):

@imqwerty

imqwerty (imqwerty):

yes \(\cal\Large\color{green}{Correct!}\)

OpenStudy (diana.xl):

Tysm. can u help with part b as well?

OpenStudy (diana.xl):

@imqwerty

OpenStudy (diana.xl):

http://prntscr.com/99dt98

imqwerty (imqwerty):

okay :) to check if (1,-2) is a solution you just put these coordinates in our inequality->\(\large y<-x+25\) if the inequality is satisfied it is a solution. OR you can just check if (1,2) lies in the shaded region If it does it is a solution to the inequality

imqwerty (imqwerty):

In this case the solution to the inequality will be all the points which lie under the shaded region. But the points lying on the dotted line(Boundary) of the graph will not be considered as solutions.

OpenStudy (diana.xl):

http://prntscr.com/99dwwp like that?

OpenStudy (diana.xl):

@imqwerty

imqwerty (imqwerty):

yeah (1,2) is a solution and now you have to write the reason and meaning of it being a solution.

OpenStudy (diana.xl):

The ordered pair is representing the amount of boys and girls which would really be the same out, so we graph it and shade it out.

imqwerty (imqwerty):

yes thats ok you can also add that the solution (1,2) follows the given inequality so it holds true.

OpenStudy (diana.xl):

thnx

imqwerty (imqwerty):

np \(\Huge\ddot\smile\)

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