Question

A cylindrical can has a horizontal base of radius 3.4 cm. It contains sufficient water so that when a sphere is placed inside, the water just covers the sphere. If the sphere fits exactly into the can, calculate
(a) The total surface area of the can in contact with the water when the shpere is inside,
(b) The depth of the water in the can before the sphere was put inside.

Answer 1

this?

Answer 2

There's no diagram with it.

Answer 3

question no.22

Answer 4

if the sphere fits into the can exactly,
then diameter of the can= diameter of the sphere

Answer 5

I think the r of sphere is 6.8, h of cylindrical is 6.8
but I'm russian and can not understand this exactly

Answer 6

for part (b) it is just
volume of water= volume of cylinder - volume of sphere

Answer 7

and yes, height also equal to diameter :)

Answer 8

cylindrical S = h*pi*r + 2*pi*r^2

Answer 9

i'm not sure about part (a)

Answer 10

WAIT S = 2 * pi *r*h + 2 * pi * r^2
But it's can so S = 2*pi*r*h + pi*r^2= pi*r*(2h+r)

Answer 11

S= 2*3.142*3.4*6.8+3.142*3.4^2
=145.29+36.32
=181.61
^Correct answer.

Answer 12

oh ok, so its just the surface area of the entire can

Answer 13

@Palvasha are we done?

Answer 14

Yeah. Thank you both of you.

Answer 15

:)