Question

an athlete jumps with the speed of 4 m/s at an angle of 23° how long does the athlete stay in the air?

Answer 1

Okay, this is something I call classic projectile.

1. Method 1: The easy way.
We have a result derived from eqn of motion as:
\[T = 2u \sin x / g\]
Just put the values.

2. Method 2: The hard way.
The vertical displacement is zero. Thus,
\[S _{y} = 0 = u _{y}t - 1/2 g t ^{2}\]
Use \[u _{y} = u \sin x\]. Put values and get the answer.
The answer is 0.64. Check it though, I mess up real bad at calculations. :)

Answer 2

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Hey i have made this to hopefully answer any questions you may have. But if it doesn't feel free to pm me c:
http://openstudy.com/users/rebeccaxhawaii#/updates/56f5205ce4b07a8c82287f75
Good Luck with you studies!
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