**WILL FAN & MEDAL** I need help with this problem The test to detect the presence of a liver disorder is 98% accurate for a person who has the disease and 97% accurate for a person who does not have the disease. If 3.5% of the people in a given population actually have the disorder, what is the probability that a randomly chosen person tests positive? A) 0.0343 B) 0.035 C) 0.06325 D) 0.02895
Hii!
HI!!
lets do it with numbers !
or not maybe @Astrophysics has a better way
It's cool you can go ahead :)
i would start by saying lets test 10,000 people
\[3.5\%\] of them have the disease, and \[3.5\%\] of \(10,000\) is \(350\) so \(350\) people have it
\[98\%\] of those 350 will test positive, and \[0.98\times 350=343\]so we know that 343 people who have it will test positive
now lets see how many of those who do not have it will test positive first off, 350 have it so \[10,000-350=9650\] so not have the disease of those \(3\%\) will also test positive
\[.03\times 9650=289.5\] so \[289.5\] will of those who do not have it will also test positive
all together, how many people test positive?
i.e. add \[289.5+343\]
632.5?
ok, then divide by \(10,000\) by moving the decimal over to get your answer
0.06325?
oh imagine that! the answer is once again C when in doubt, charlie out
Thanks a lot for your help, you explained it very well :)
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