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Mathematics 8 Online
OpenStudy (asad786):

WILL MEDAL http://prntscr.com/99qlsp

OpenStudy (astrophysics):

|dw:1449118431550:dw|

OpenStudy (astrophysics):

So note we have to solve for a, which mean we want a on it's own and in the numerator. So see how 23 is being divided by a, we can put it as following \[23 \times \frac{ 1 }{ a } =8\]

OpenStudy (asad786):

huh?

OpenStudy (astrophysics):

As it's being divided by a, and we have 8 on that side, we don't have to do much with the 23, so you can "cross multiply" 1/a with 8

OpenStudy (astrophysics):

To put it simply what happens if we multiply both sides by a?

OpenStudy (asad786):

but whats a

OpenStudy (astrophysics):

a is what you're solving for it's called a variable

OpenStudy (astrophysics):

You want a on its own

OpenStudy (asad786):

i still don't get it

OpenStudy (asad786):

hello

OpenStudy (asad786):

but i think answer is a

OpenStudy (astrophysics):

For example |dw:1449118743002:dw| then you can divide by 7 to get a on its own

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